Answer
$\dfrac{5x^{2}-500}{35x+350}=\dfrac{x-10}{7}$
Work Step by Step
$\dfrac{5x^{2}-500}{35x+350}$
Take out common factor $5$ in the numerator and common factor $35$ in the denominator:
$\dfrac{5x^{2}-500}{35x+350}=\dfrac{5(x^{2}-100)}{35(x+10)}=...$
Factor $x^{2}-100$ and simplify:
$...=\dfrac{5(x-10)(x+10)}{35(x+10)}=\dfrac{5(x-10)}{35}=\dfrac{x-10}{7}$