Answer
$\dfrac{3x-9}{4x-16}=\dfrac{3(x-3)}{4(x-4)}$
Work Step by Step
$\dfrac{3x-9}{4x-16}$
Take out common factor $3$ in the numerator and common factor $4$ in the denominator:
$\dfrac{3x-9}{4x-16}=\dfrac{3(x-3)}{4(x-4)}$
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