Answer
$\dfrac{x-3}{x^{2}-6x+9}=\dfrac{1}{x-3}$
Work Step by Step
$\dfrac{x-3}{x^{2}-6x+9}$
The denominator is a perfect square trinomial. Factor it and then simplify:
$\dfrac{x-3}{x^{2}-6x+9}=\dfrac{x-3}{(x-3)^{2}}=\dfrac{1}{x-3}$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.