Answer
$\dfrac{x^{2}+7x+10}{x^{2}-3x-10}=\dfrac{x+5}{x-5}$
Work Step by Step
$\dfrac{x^{2}+7x+10}{x^{2}-3x-10}$
Factor the numerator:
$\dfrac{x^{2}+7x+10}{x^{2}-3x-10}=\dfrac{(x+5)(x+2)}{x^{2}-3x-10}=...$
Factor the denominator and simplify:
$...=\dfrac{(x+5)(x+2)}{(x+2)(x-5)}=\dfrac{x+5}{x-5}$
