Answer
$\dfrac{4-x^{2}}{x-2}=-x-2$
Work Step by Step
$\dfrac{4-x^{2}}{x-2}$
Factor the numerator:
$\dfrac{4-x^{2}}{x-2}=\dfrac{(2-x)(2+x)}{x-2}=...$
Change the sign of the denominator. To do so, also change the sign of the fraction. After that, simplify:
$...=-\dfrac{(2-x)(2+x)}{2-x}=-(2+x)=-x-2$
