Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.1 - Simplifying Rational Expressions - Exercise Set - Page 490: 49

Answer

$\dfrac{2x^{2}-8}{4x-8}=\dfrac{x+2}{2}$

Work Step by Step

$\dfrac{2x^{2}-8}{4x-8}$ Take out common factor $2$ in the numerator and common factor $4$ in the denominator. $\dfrac{2x^{2}-8}{4x-8}=\dfrac{2(x^{2}-4)}{4(x-2)}=...$ Now, factor $x^{2}-4$ and simplify: $...=\dfrac{2(x-2)(x+2)}{4(x-2)}=\dfrac{2(x+2)}{4}=\dfrac{x+2}{2}$
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