Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set - Page 379: 67

Answer

$9y^{2}+30y+25$

Work Step by Step

$(3y+5)^{2}=(3y+5)(3y+5)=3y(3y+5)+5(3y+5)=(3y)(3y)+(3y)(5)+(5)(3y)+(5)(5)=9y^{2}+15y+15y+25=9y^{2}+30y+25$
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