Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set - Page 379: 37

Answer

$12x^{4}+25x^{2}+7$

Work Step by Step

$(3x^{2}+1)(4x^{2}+7)=3x^{2}(4x^{2}+7)+1(4x^{2}+7)=(3x^{2})(4x^{2})+(3x^{2})(7)+(1)(4x^{2})+(1)(7)=12x^{2+2}+21x^{2}+4x^{2}+7=12x^{4}+21x^{2}+4x^{2}+7=12x^{4}+25x^{2}+7$
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