Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set: 35

Answer

$x^{2}+\frac{1}{3}x-\frac{2}{9}$

Work Step by Step

$(x+\frac{2}{3})(x-\frac{1}{3})=x(x-\frac{1}{3})+\frac{2}{3}(x-\frac{1}{3})=(x)(x)+(x)(-\frac{1}{3})+(\frac{2}{3})(x)+(\frac{2}{3})(-\frac{1}{3})=x^{2}-\frac{1}{3}x+\frac{2}{3}x-\frac{2}{9}=x^{2}+\frac{1}{3}x-\frac{2}{9}$
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