Answer
$x^{2}+\frac{1}{3}x-\frac{2}{9}$
Work Step by Step
$(x+\frac{2}{3})(x-\frac{1}{3})=x(x-\frac{1}{3})+\frac{2}{3}(x-\frac{1}{3})=(x)(x)+(x)(-\frac{1}{3})+(\frac{2}{3})(x)+(\frac{2}{3})(-\frac{1}{3})=x^{2}-\frac{1}{3}x+\frac{2}{3}x-\frac{2}{9}=x^{2}+\frac{1}{3}x-\frac{2}{9}$
