Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set - Page 379: 40

Answer

$16x^{2}-38x+12$

Work Step by Step

$(8x-3)(2x-4)=8x(2x-4)-3(2x-4)=(8x)(2x)+(8x)(-4)-3(2x)-3(-4)=16x^{1+1}-32x-6x+12=16x^{2}-32x-6x+12=16x^{2}-38x+12$
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