Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set: 31

Answer

$x^{2}+7x+12$

Work Step by Step

$(x+4)(x+3)=x(x+3)+4(x+3)=(x)(x)+(x)(3)+(4)(x)+(4)(3)=x^{2}+3x+4x+12=x^{2}+7x+12$
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