Answer
$4x^{4}-3x^{3}+\frac{1}{2}x^{2}$
Work Step by Step
$\frac{1}{2}x^{2}(8x^{2}-6x+1)=(\frac{1}{2}x^{2})(8x^{2})+(\frac{1}{2}x^{2})(-6x)+(\frac{1}{2}x^{2})(1)=4x^{2+2}+(-3x^{2+1})+\frac{1}{2}x^{2}=4x^{4}+(-3x^{3})+\frac{1}{2}x^{2}=4x^{4}-3x^{3}+\frac{1}{2}x^{2}$