Answer
$x^{2}+\frac{1}{5}x-\frac{6}{25}$
Work Step by Step
$(x+\frac{3}{5})(x-\frac{2}{5})=x(x-\frac{2}{5})+\frac{3}{5}(x-\frac{2}{5})=(x)(x)+(x)(-\frac{2}{5})+(\frac{3}{5})(x)+(\frac{3}{5})(-\frac{2}{5})=x^{2}-\frac{2}{5}x+\frac{3}{5}x-\frac{6}{25}=x^{2}+\frac{1}{5}x-\frac{6}{25}$
