Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set: 30

Answer

$3y^{4}-2y^{3}+\frac{1}{3}y^{2}$

Work Step by Step

$\frac{1}{3}y^{2}(9y^{2}-6y+1)=(\frac{1}{3}y^{2})(9y^{2})+(\frac{1}{3}y^{2})(-6y)+(\frac{1}{3}y^{2})(1)=3y^{2+2}+(-2y^{2+1})+\frac{1}{3}y^{2}=3y^{4}+(-2y^{3})+\frac{1}{3}y^{2}=3y^{4}-2y^{3}+\frac{1}{3}y^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.