Answer
$a^{4}-a^{3}-6a^{2}+7a+14$
Work Step by Step
$(a+2)(a^{3}-3a^{2}+7)=a(a^{3}-3a^{2}+7)+2(a^{3}-3a^{2}+7)=(a)(a^{3})+(a)(-3a^{2})+(a)(7)+(2)(a^{3})+(2)(-3a^{2})+(2)(7)=a^{4}-3a^{3}+7a+2a^{3}-6a^{2}+14=a^{4}-a^{3}-6a^{2}+7a+14$
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