Answer
$\frac{27a^{6}}{b^{12}}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $(3a^{2}b^{-4})^{3}=3^{3}\times(a^{2})^{3}\times(b^{-4})^{3}=27\times a^{2\times3}\times b^{-4\times3}=27\times a^{6}\times b^{-12}=27\times a^{6}\times \frac{1}{b^{12}}=\frac{27a^{6}}{b^{12}}$.