Answer
$\frac{1}{64}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $(-2)^{-6}=\frac{1}{(-2)^{6}}=\frac{1}{-2\times-2\times-2\times-2\times-2\times-2}=\frac{1}{64}$.