Answer
$\frac{1}{x^{2}}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $\frac{(x^{2})^{5}}{(x^{4})^{3}}=\frac{x^{2\times5}}{x^{4\times3}}=\frac{x^{10}}{x^{12}}=x^{10-12}=x^{-2}=\frac{1}{x^{2}}$.