Answer
$\frac{1}{x^{15}y^{9}}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $(x^{5}y^{3})^{-3}=(x^{5})^{-3}(y^{3})^{-3}=x^{5\times-3}\times y^{3\times-3}=x^{-15}y^{-9}=\frac{1}{x^{15}y^{9}}$.
