Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set: 30

Answer

$x^{8}$

Work Step by Step

$\frac{(x^{2})^{8}x}{x^{9}}=\frac{x^{2\times8}\times x}{x^{9}}=\frac{x^{16}\times x}{x^{9}}=\frac{x^{16+1}}{x^{9}}=\frac{x^{17}}{x^{9}}=x^{17-9}=x^{8}$
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