Answer
$-\frac{6}{7y^{2}z^{5}}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $\frac{6x^{2}y^{3}z^{0}}{-7x^{2}y^{5}z^{5}}=-\frac{6}{7}\times x^{2-2}\times y^{3-5}\times z^{0-5}=-\frac{6}{7}\times x^{0}\times y^{-2}\times z^{-5}=-\frac{6}{7}\times1\times\frac{1}{y^{2}}\times\frac{1}{z^{5}}=-\frac{6}{7y^{2}z^{5}}$.
