Answer
$\frac{5}{6}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $3^{-1}+2^{-1}=\frac{1}{3}+\frac{1}{2}=\frac{1\times2}{3\times2}+\frac{1\times3}{2\times3}=\frac{2}{6}+\frac{3}{6}=\frac{2+3}{6}=\frac{5}{6}$.