Answer
$-\frac{y^{3}}{3}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $\frac{-5x^{4}y^{5}}{15x^{4}y^{2}}=\frac{-5}{15}\times x^{4-4}\times y^{5-2}=-\frac{1}{3}\times x^{0}\times y^{3}=-\frac{1}{3}\times 1\times y^{3}=-\frac{y^{3}}{3}$.
