Answer
$r^{6}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $\frac{r}{r^{-3}r^{-2}}=r\times r^{3}\times r^{2}=r^{1+3+2}=r^{6}$.
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