Answer
See explanation.
Work Step by Step
The mirror surface is convex so R=-3.00 cm.
The focal length is half the radius of curvature.
$$f=\frac{1}{2}r=\frac{1}{2}(-3.00cm)=-1.50cm$$
Use the mirror equation.
$$\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$$
Solve for the image distance.
$$s’=\frac{sf}{s-f}=\frac{(15cm)(-1.5cm)}{15cm-(-1.5cm)}=-1.36 cm$$
The image is 1.36 cm behind the surface. In other words, it is 3.00cm-1.36cm=1.64 cm from the center of the ornament, on the same side of the center as the object.
Calculate the magnification.
$$m=-\frac{s’}{s}=-\frac{-1.3636cm}{15.0cm}=+0.0909$$
The image is virtual, upright and much smaller than the object.
