University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 34 - Geometric Optics - Problems - Exercises - Page 1152: 34.26



Work Step by Step

The image and object distances are related to the indices of refraction and to the radius of curvature. $$\frac{n_a}{s}+\frac{n_b}{sā€™}=\frac{n_b-n_a}{R}$$ $$\frac{n_a}{14.0cm}+\frac{1.60}{-9.00cm}=\frac{1.60-n_a}{-4.00cm}$$ $$0.071n_a-0.1778=-0.4+0.25n_a$$ $$n_a=1.24$$ This is a reasonable refractive index for a liquid.
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