Answer
0.213 mm.
Work Step by Step
Find the magnification. We see that $s \gg f$ so $s’=f=1.75m$.
$$m=-\frac{s’}{s}=-\frac{1.75m}{5.58\times10^{10}m}=-3.14\times10^{-11}$$
Now find the image height.
$$|y’|=|m||y|=(3.14\times10^{-11})(6.794\times10^6m)=0.213mm$$
