University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 34 - Geometric Optics - Problems - Exercises - Page 1152: .34.19

Answer

3.31 m.

Work Step by Step

For a plane refracting surface, $\frac{n_a}{s}+\frac{n_b}{s’}=0$. We know that $n_a=1.00$ and we are looking for s. We see that $n_b = 1.33$ because the medium is water. The image is 5.20m - 0.80m = 4.40m above the surface of the water, so s’=-4.40 m. $$\frac{n_a}{s}+\frac{n_b}{s’}=0$$ $$\frac{1.00}{s}+\frac{1.33}{-4.40m}=0$$ $$s=(4.40m)\frac{1.00}{1.33}=3.31m$$ In reality, the diving board is closer to the water than it looks to the swimmer.
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