Answer
D
Work Step by Step
$T_H=T_{sat,\ 1.4\ MPa}=52.40°C$
$T_L=T_{sat,\ 0.16\ MPa}=-15.75°C$
$COP_R=\dfrac{1}{\frac{T_H}{T_L}-1}$
$COP=3.77$
$COP_R=\dot{Q}_L/\dot{W}_i,\ \dot{W}_i=3\ kW$
$\dot{Q}_L=11.3\ kJ/s$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 326: 6-162
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