Answer
$T_H^*=\dfrac{T_HT_L}{T_H-2T_L}$
Work Step by Step
$\eta=1-\frac{T_L}{T_H}$
$\eta^*=1-\frac{T_L}{T_H^*}=2\eta$
$1-\frac{T_L}{T_H^*}=2(1-\frac{T_L}{T_H})$
$2\frac{T_L}{T_H}-1=\frac{T_L}{T_H^*}$
$T_H^*=\dfrac{T_HT_L}{T_H-2T_L}$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 326: 6-153
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