Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 326: 6-161

Answer

C

Work Step by Step

$\eta=1-\frac{T_L}{T_H}$ $T_L=323\ K,\ T_H=1273\ K$ $\eta=0.746$ $\eta = \dot{W}_e/\dot{Q}_H,\ \dot{Q}_H=100\ kJ/s$ $\dot{W}_e=74.6\ kW$
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