Answer
B
Work Step by Step
$W=\ 85/year\div\ 0.09/kWh=944.4\ kWh/year$
$Q=W.\eta,\ \eta=0.90$
$Q=850\ kWh/year$
$Q=mc_p\Delta T.\ c_p=4.18\ kJ/kg.°C,\ \Delta T=(45-18)°C$
$m=27.1\times10^3\ kg$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 326: 6-158
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