Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 326: 6-157

Answer

C

Work Step by Step

$\dot{W}=\dot{m}c_p\Delta T/COP$ $\dot{m}=10\ kg/h,\ c_p=4.18\ kJ/kg.°C,\ \Delta T=(23-6)°C,\ COP=3.1$ $\dot{W}=229.2\ kJ/h=63.67\ W$
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