Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 322: 6-126

Answer

$P_{min}=P_{sat,T_L}=356\ kPa$

Work Step by Step

$COP_R=\dfrac{1}{1-\frac{T_L}{T_H}}$ $T_H/T_L=1.2$ $COP_R=5$ $COP_R=Q_L/W_i,\quad W_i=22\ kJ$ $Q_L=110\ kJ$ $Q_H=W_i+Q_L$ $Q_H=132\ kJ$ $q_H=Q_H/m,\quad m=0.96\ kg$ $q_H=137.5\ kJ/kg=\Delta h_v\ \rightarrow T_H=61.3°C$ $T_L=278.6\ K=5.6°C$ $P_{min}=P_{sat,T_L}=356\ kPa$
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