Answer
a) $COP_{HP}=13.4$
b) $\dot{W}_i=2.93\ hp$
Work Step by Step
$COP_{HP}=\dfrac{1}{1-\frac{T_L}{T_H}}$
Given $T_L=495°R,\ T_H=535°R$
$COP_{HP}=13.4$
$\dot{Q}_H=2500\ Btu/h/°F\times (75-35)°F=100,000\ Btu/h$
$COP_{HP}=\dot{Q}_H/\dot{W}_i$
$\dot{W}_i=2.93\ hp$
