Answer
$Q_H=640\ kJ$
$Q_L=140\ kJ$
Work Step by Step
$\eta=1-\frac{T_L}{T_H}$
$T_L=50°C,\ T_H=1200°C$
$\eta=0.781$
$\eta = W_e/Q_H$
$W_e=500\ kJ$
$Q_H=640\ kJ$
$Q_H=W_e+Q_L$
$Q_L=140\ kJ$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 322: 6-121
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