Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 322: 6-124

Answer

$\Delta t=19.2\ min$

Work Step by Step

$Q_H=mc_v\Delta T$ $m=1500\ kg,\ c_v=0.718\ kJ/kg.K,\ \Delta T=(22-7)°C=15°C$ $Q_H=16,155\ kJ$ $COP_{HP}=\dot{Q}_H/\dot{W}_i,\ COP=2.8,\ \dot{W}_i=5\ kW$ $\dot{Q}_H=14\ kW$ $\dot{Q}_H=Q_H/\Delta t$ $\Delta t=1154s=19.2\ min$
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