Answer
$T_L=428°R$
Work Step by Step
$\dot{Q}_H=\dot{W}_i+\dot{Q}_L$
$\dot{Q}_H=32,000\ Btu/h,\ \dot{W}_i=1.8\ kW$
$\left (\dfrac{\dot{Q}_H}{\dot{Q}_L}\right)_{rev}=\dfrac{T_H}{T_L}$
$T_H=530°R$
$T_L=428°R$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 322: 6-122E
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