Answer
$T_L=611°C$
Work Step by Step
$\eta = \dot{W}_e/\dot{Q}_H$
Given $\eta=0.4,\ \dot{W}_e=500\ kJ$
$\dot{Q}_H=1250\ kJ$
$\dot{Q}_H=\dot{W}_e+\dot{Q}_L$
$\dot{Q}_L=750\ kJ$
$\eta=1-\frac{T_L}{T_H},\quad T_H=1473K$
$T_L=883.8K=611°C$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 317: 6-81
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