Answer
a) $T_H=77.2\ K$
b) $\eta=0.615=61.5\%$
Work Step by Step
$\left (\frac{Q_H}{Q_L}\right)_{rev}=\frac{T_H}{T_L}$
Given $Q_L=250\ kJ,\ Q_H=650\ kJ,\ T_L=297\ K$
$T_H=77.2\ K$
$\eta=1-\dfrac{T_L}{T_H}$
$\eta=0.615=61.5\%$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 317: 6-76
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
