Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 317: 6-75E

Answer

a) $\dot{W}_e=23.1\ hp$ b) $T_H=1155.6°R$

Work Step by Step

$\eta=1-\frac{\dot{Q}_L}{\dot{Q}_H}$ $\eta=0.55,\ \dot{Q}_L=800\ Btu/min$ $\dot{Q}_H=1777.8\ Btu/min$ $\eta = \dot{W}_e/\dot{Q}_H$ $\dot{W}_e=977.8\ Btu/min=23.1\ hp$ $\eta=1-\frac{T_L}{T_H}$, $T_L=520°R$ $T_H=1155.6°R$
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