Answer
$\dot{W}_e=653\ kW$
Work Step by Step
$\eta=1-\frac{T_L}{T_H}$
Given $T_H=477°C=750\ K,\ T_L=25°C=298\ K$
$\eta=0.60=60\%$
$\eta = \dot{W}_e/\dot{Q}_H,\quad \dot{Q}_H=65000\ kJ/min$
$\dot{W}_e=39000\ kJ/min=653\ kW$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 317: 6-78
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