Answer
a) $\eta=70\%$
b) $\dot{W}_e=9.33\ kW$
Work Step by Step
$\eta=1-\dfrac{T_L}{T_H}$
With $T_L=300\ K,\ T_H=1000\ K$
$\eta=0.70=70\%$
$\eta = \dot{W}_e/\dot{Q}_H,\ \dot{Q}_H=800\ kJ/min$
$\dot{W}_e=560\ kJ/min=9.33\ kW$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 317: 6-77
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