Answer
$Q_L=3.646\times10^{12}\ kWh$
Work Step by Step
Since
$\eta = W_e/Q_H$
$Q_H=W_e+Q_L$
which leads to
$\eta(W_e+Q_L) = W_e$
Given $\eta=0.34,\ W_e=1.878\times10^{12}\ kWh$:
and solving for the heat loss:
$Q_L=3.646\times10^{12}\ kWh$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 313: 6-24
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