Answer
$\eta=30\%$
Work Step by Step
$\dot{Q}_H=q\dot{m}$
Given $q=30000\ kJ/kg,\ \dot{m}=60000\ kg/h$
$\dot{Q}_H=1.8\times10^9\ kJ/h=500\ MW$
$\eta = \dot{W}_e/\dot{Q}_H$
since $\dot{W}_e=150\ MW$
$\eta=0.30=30\%$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 313: 6-22
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