Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 313: 6-17E

Answer

$\dot{W}_e=4.716\ hp$

Work Step by Step

With $\eta = \dot{W}_e/\dot{Q}_H$ Given $\eta = 0.40,\ \dot{Q}_H=3\times10^4\ Btu/h$ $\dot{W}_e=1.2\times10^4\ Btu/h=4.716\ hp$
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