Answer
$q_H=909\ kJ/kg$
Work Step by Step
Given:
$\eta = w_e/q_H$
$q_H=w_e+q_L$
we derive:
$(1-\eta)q_H=q_L$
With $q_L=500\ kJ/kg,\ \eta=0.45$
$q_H=909\ kJ/kg$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 313: 6-21
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