Answer
$\eta=25.6\%$
Work Step by Step
$\dot{Q}_H=(\rho\dot{V})q$
Given $\rho=0.8\ kg/L,\ \dot{V}=22\ L/h,\ q=44000kJ/kg$
$\dot{Q}_H=774.4 MJ/h=215.1\ kW$
Since $\eta = \dot{W}_e/\dot{Q}_H$ and $\dot{W}_e=55\ kW$:
$\eta=0.256=25.6\%$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 313: 6-23
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