Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems - Page 133: 32

Answer

The acceleration due to gravity on the hypothetical planet is $2.5 ~m/s^2$

Work Step by Step

Let $g_p$ be the acceleration due to gravity on the hypothetical planet and let $g_E$ be the acceleration due to gravity on the Earth: $g_p = G \frac{m_E}{(2r_E)^2}$.......(1) $g_p = \frac{1}{4}\times G \frac{m_E}{(r_E)^2}$........(2) Substituting (1) in (2): $g_p = \frac{1}{4}\times g_E$ $g_p = \frac{1}{4}\times (9.8 ~m/s^2)$ $g_p = 2.5 ~m/s^2$ The acceleration due to gravity on the hypothetical planet is $2.5 ~m/s^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.