Answer
930 m
Work Step by Step
When the pilot pulls his plane out of the dive, his plane follows the path of a semi-circle, thus we will use the equation $F = mv^{2}/r$ and $F = ma$
v = 270 m/s
a = 8.0g
$F = ma = mv^{2}/r$
$F = a = v^{2}/r$
$8.0g = 270^{2}/r$
$r= 270^{2}/8.0g$
$r = 930 m$
